Ток и напряжение двухполюсника: <em>i</em>(<em>t</em>) = <em>I</em><sub>1</sub>√2 sin(ω<em>t</em> + 45°) A, <em>u</em>(<em>t</em>) = <em>U</em><sub>0</sub> + <em>U</em><sub>1</sub>√2 sin(ω<em>t</em> – 45°) B. Указать эквивалентную схему двухполюсника.<img src="/close/store/examRes/%7B0112D70C-9A0B-43E5-8CB5-25053571B174%7D/LT55-54.jpg" /><img src="/close/store/examRes/%7B0112D70C-9A0B-43E5-8CB5-25053571B174%7D/LT55-51.jpg" /><img src="/close/store/examRes/%7B0112D70C-9A0B-43E5-8CB5-25053571B174%7D/LT55-53.jpg" /><img src="/close/store/examRes/%7B0112D70C-9A0B-43E5-8CB5-25053571B174%7D/LT55-523.jpg" /><img src="/close/store/examRes/%7B0112D70C-9A0B-43E5-8CB5-25053571B174%7D/LT55-52.jpg" /> <img src="/img/42/524546d8f28da03cd5e0ec5717.jpg" />, <img src="/img/bc/feb9837d343418b3f4b2a374cd.jpg" />, <img src="/img/31/5eecd24f4a636851bde9747a57.jpg" />, <img src="/img/d4/57aadf132e6e3351eecab4f808.jpg" />, <img src="/img/28/477159b4c6ec6d56a90e20b5a9.jpg" />